2 claims investigated in this paper
| 1 | Theorem 1(i)Theorem · main result | False as stated | AIPrivate humanpartial source check |
| 2 | Lemma A1 proof: function-space stepLemma · auxiliary result | Missing assumption | AIPrivate humanpartial source check |
Theorem 1(i)
False as stated
The literal one-way order condition admits a game satisfying Assumption 1 with no distributional equilibrium.
Theorem 1(i). Under Assumption 1, there exists a greatest and a least distributional equilibrium of the game.
What was found
Take types [0,1] with Lebesgue probability, actions {0,1}, a constant feasible-action set, and equality as the partial order on type-action pairs. Let p be the mass choosing action 1. Make action 1 uniquely optimal when p<1/2 and action 0 uniquely optimal when p≥1/2. Equality is permitted by the printed one-way order condition and makes the induced stochastic order equality, so the single-crossing condition is vacuous. Any equilibrium with p<1/2 would force p=1; any equilibrium with p≥1/2 would force p=0. Hence no distributional equilibrium exists.
What was tested
The exact assumption matrix, the induced stochastic order, strict best replies and the equilibrium contradiction were checked in a separate informed hostile validation. A strengthened four-action witness also defeats the possible rescue that greatest/least feasible distributions or chain completeness were intended as additional premises.
Does not establish
- The record does not claim that the authors' intended stronger order condition is false.
- Applications that independently impose a product or same-type action order are not claimed to fail.
- No downstream paper is claimed to be incorrect without checking its own assumptions.
Repair
Local repair proposed. A same-type fiber condition requiring action order to imply pair order excludes the counterexample and supplies a comparison used in the proof. The appendix chain-completeness argument still needs a separate valid justification.
Verification
- Separate AI recheckOct 2026 · informed. A separate informed hostile-validation session reconstructed the assumptions, tested rescue attempts and confirmed the exact counterexample.
- Reproduced by the researcherNot done.
- External human verificationNot done.
- Written author agreementNot given.
- Qualifying human confirmation (private)Oct 2026. A qualifying human confirmation is recorded in the private research file. Its source and correspondence are not disclosed.
Confirmed: 2 kinds of check, 1 by a human. The standard requires two kinds, at least one by a human.
Source
Partial check, pp. 503–504. The canonical source lock is partial because the historical decisive check used extracted final publisher text rather than a complete rendered-page verification. The theorem wording and order assumptions were rechecked on the publisher-hosted article during release preparation.
Lemma A1 proof: function-space step
Missing assumption
Measurability and isotonicity do not imply continuity, so the asserted inclusion in C(X) does not follow.
Lemma A1 proof: function-space step. In the proof of Lemma A1, M(X)-M(X) is asserted to be a Riesz subspace of the continuous functions C(X).
What was found
Under the equality order, every bounded measurable function is isotone. Discontinuous indicator functions therefore belong to M(X), so M(X) and M(X)-M(X) need not be contained in C(X). The Stone-Weierstrass step cannot be justified from the displayed definition as written.
What was tested
The appendix definitions and the claimed Riesz-subspace step were traced in the historical audit and independently attacked in the hostile validation.
Does not establish
- This defect alone is not claimed to falsify the conclusion of Lemma A1.
- The record does not claim that no alternative proof of the relevant measure-order result exists.
- The record does not publish or rely on any private proposed correction.
Repair
Local repair proposed. The function class or the proof must be strengthened so that the functions used in the Stone-Weierstrass argument are continuous; a complete repair of the constrained-measure chain-completeness argument is not claimed here.
Verification
- Separate AI recheckOct 2026 · informed. A separate informed hostile-validation session confirmed the mismatch between the displayed definition of M(X) and the continuity required by the proof.
- Reproduced by the researcherNot done.
- External human verificationNot done.
- Written author agreementNot given.
- Qualifying human confirmation (private)Oct 2026. A qualifying human confirmation is recorded in the private research file. Its source and correspondence are not disclosed.
Confirmed: 2 kinds of check, 1 by a human. The standard requires two kinds, at least one by a human.
Source
Partial check, pp. 519. The canonical source lock is partial because the historical check used extracted final publisher text. The publisher-hosted article was rechecked during release preparation and still defines M(X) as measurable and bounded before asserting the subspace inclusion.
Authors and corrections
- Authors
- Not disclosed.
- Correction
- None published.
History
- October 2026Theorem-level counterexample and appendix defect identified and separately rechecked
- October 2026Published-source text checked; canonical VOR level remains partial
- 7 November 2026Record version 1.0 released
Versions
- Version 1.07 November 2026First release.
Released versions are never edited; each keeps its own address.
Use of AI in this case
AI systems were used for discovery and separate hostile rechecking. Confirmation also includes a qualifying human check recorded privately. Private correspondence is not disclosed, and AI agreement is not treated as human verification.